(-2x^4y/4y^2)^0

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Solution for (-2x^4y/4y^2)^0 equation: 


D( x )

((-2*x^4*y)/4)*y^2 = 0

((-2*x^4*y)/4)*y^2 = 0

((-2*x^4*y)/4)*y^2 = 0

-1/2*x^4*y^3 = 0 // : -1/2*y^3

x^4 = 0

x = 0

x in (-oo:0) U (0:+oo)

(((-2*x^4*y)/4)*y^2)^0 = 0

1 = 0

(((-2*x^4*y)/4)*y^2)^0 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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